WebAug 12, 2024 · This way we can reverse a number. Step 1: Convert the number into a string. Step 2: Check whether the first character is a number or a minus sign (-). Step 3: If it’s a minus sign, construct a new string from the last character of the original string to the second character from start. Webreverse = num3+ num2+ num1; does not give what you are expecting. You should write instead reverse = 100 * num3 + 10 * num2 + num1; In fact you need not to calculate the digits. Just enter a three-digit number as three separate digits.:) For example

Reverse a number using Stack - Coding Ninjas

WebTo reverse a given integer in C programming, pop the last digit of the given number in a loop, and append it to a new number. At the end of iteration, we end up with the reversed number in the result. C Program In the following program, we read a number to n from user via console input, and reverse this number. main.c #include WebOct 3, 2016 · 1: Use a loop to access all digits of a number. 2: Inside loop, use modulus operator to extract digits one by one. 3: Add extracted digits to a new variable "reverse". 4: Divide the number by 10 so for next loop iteration, it will point to next digit. ian o\u0027brien architects

Algorithm and Flowchart to Print the Reverse of the Number

WebJul 18, 2013 · Hi A small correction Your code returns the first digit (not last digit) of the entered number. Here is the reason You are calculating revNum after returning some value like this return (rev (number/10)+revNum); revNum= (number%10)*sum; sum=sum/10; hence the second statement has no effect. Also revNum is a local variable Web// c++ program to reverse the number using stack #include using namespace std; int main() { int n = 2545; // declaring the empty stack stack st; // pushing the digits into the stack while (n > 0) { st.push(n % 10); n /= 10; } // we will store the reverse number into this variable WebMar 17, 2024 · Consider reverse number be rev_num =0. Step 2. Now we will use the given formula, ie. rev_num = rev_num*10 + num%10; num = num / 10; As we can see each time … ian o\\u0027connor coach k